Given information:
- Set A= {1,2,3,5,6,10,15,30}
- N is an element of set A
- PQR = N, where P, Q, and R are integers

To find: Number of positive integral solutions of PQR = N

Approach:
- As N is an element of set A, we can find all the possible values of P, Q, and R for each N in the set A
- Then, we can count the number of positive integral solutions of PQR for all the values of N in set A
- Finally, we can add up all the solutions to get the total number of positive integral solutions of PQR = N

Let's find the possible values of P, Q, and R for each N in set A:

1. When N = 1
- PQR = 1
- There is only one solution for P, Q, and R: P=1, Q=1, and R=1
- Total number of solutions = 1

2. When N = 2
- PQR = 2
- There are three possible solutions for P, Q, and R: P=1, Q=2, and R=1; P=2, Q=1, and R=1; P=2, Q=1, and R=1
- Total number of solutions = 3

3. When N = 3
- PQR = 3
- There are two possible solutions for P, Q, and R: P=1, Q=3, and R=1; P=3, Q=1, and R=1
- Total number of solutions = 2

4. When N = 5
- PQR = 5
- There are two possible solutions for P, Q, and R: P=1, Q=5, and R=1; P=5, Q=1, and R=1
- Total number of solutions = 2

5. When N = 6
- PQR = 6
- There are four possible solutions for P, Q, and R: P=1, Q=2, and R=3; P=1, Q=3, and R=2; P=2, Q=1, and R=3; P=2, Q=3, and R=1
- Total number of solutions = 4

6. When N = 10
- PQR = 10
- There are six possible solutions for P, Q, and R: P=1, Q=2, and R=5; P=1, Q=5, and R=2; P=2, Q=1, and R=5; P=2, Q=5, and R=1; P=5, Q=1, and R=2; P=5, Q=2, and R=1
- Total number of solutions = 6

7. When N = 15
- PQR = 15
- There are four possible solutions for P, Q, and R: P=1, Q=3, and R=5; P=1, Q=5, and R=3; P=3, Q=1, and R=5; P=